If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-17x-285=0
a = 2; b = -17; c = -285;
Δ = b2-4ac
Δ = -172-4·2·(-285)
Δ = 2569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{2569}}{2*2}=\frac{17-\sqrt{2569}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{2569}}{2*2}=\frac{17+\sqrt{2569}}{4} $
| 1/9x+5=1/7(x+27) | | 432=(3x)(x) | | -13=5-6w | | (1/4)^2x+3=2^5x+4 | | 5y-2=-52 | | (1/4)^2x+3=2^5x/4 | | 3r=2r+20 | | -2=x/8-2 | | 6+(2x)=90 | | 14/17=p/10 | | 6+2x=60 | | -1/5(b+2)+3b=-1 | | 13+x+4=12x+6 | | 2(2x-3)+6=4x | | (3m+1)-2m=0 | | -2(x+5)=4(x-25) | | 81^2x-5=27^3x+2 | | 3(x-1)=9(x-7) | | 2^12x+4=2^20x | | 3(x-1)=9(x-25) | | 2x3+5x2+4x=0 | | 190+0.25x=430 | | 5z+4/4-2z-7/3=1 | | 3(6+x)=69 | | 6c-5=3c+2 | | x-40=24 | | 30=x-19 | | 2(v+7)=-2v-10 | | 53+b=97 | | 9x+47=-7x+25 | | -4/5p=8 | | 40-2x=10+3x |